5p^2-36p=-7

Solution for 5p^2-36p=-7 equation:

5p^2-36p=-7

We move all terms to the left:

5p^2-36p-(-7)=0

We add all the numbers together, and all the variables

5p^2-36p+7=0

a = 5; b = -36; c = +7;
Δ = b2-4ac
Δ = -362-4·5·7
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-34}{2*5}=\frac{2}{10}
=1/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+34}{2*5}=\frac{70}{10}
=7
$